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Interior

Interior

The points enclosed by a geometric figure.

Note: Interior points cannot be vertices or lie on a figure's sides, circumference, edges, faces, or surface.

 

Two pentagons: one outline only (exterior), one with shaded interior region, labeled "Interior of a pentagon

 

See also

Polygon interior, disk

Key Formula

P is an interior point of figure F    P is enclosed by F and PFP \text{ is an interior point of figure } F \iff P \text{ is enclosed by } F \text{ and } P \notin \partial F
Where:
  • PP = A point being tested
  • FF = A geometric figure (polygon, circle, polyhedron, etc.)
  • F\partial F = The boundary of F — its sides, edges, vertices, circumference, faces, or surface

Worked Example

Problem: A triangle has vertices at A(0, 0), B(6, 0), and C(3, 6). Determine whether the point P(3, 2) is in the interior of the triangle.
Step 1: Compute the area of triangle ABC using the coordinate formula.
AreaABC=12xA(yByC)+xB(yCyA)+xC(yAyB)=120(06)+6(60)+3(00)=120+36+0=18\text{Area}_{ABC} = \frac{1}{2}|x_A(y_B - y_C) + x_B(y_C - y_A) + x_C(y_A - y_B)| = \frac{1}{2}|0(0-6)+6(6-0)+3(0-0)| = \frac{1}{2}|0+36+0| = 18
Step 2: Compute the areas of the three sub-triangles formed by P and each pair of vertices: triangles PAB, PBC, and PCA.
AreaPAB=123(00)+0(02)+6(20)=120+0+12=6\text{Area}_{PAB} = \frac{1}{2}|3(0-0)+0(0-2)+6(2-0)| = \frac{1}{2}|0+0+12| = 6
Step 3: Continue with the other two sub-triangles.
\text{Area}_{PBC} = \frac{1}{2}|3(0-6)+6(6-2)+3(2-0)| = \frac{1}{2}|-18+24+6| = 6$$ $$\text{Area}_{PCA} = \frac{1}{2}|3(6-0)+3(0-2)+0(2-6)| = \frac{1}{2}|18-6+0| = 6
Step 4: Add the three sub-triangle areas and compare to the total area.
6+6+6=18=AreaABC6 + 6 + 6 = 18 = \text{Area}_{ABC}
Step 5: Because the sum equals the total area and none of the three sub-triangle areas is zero, P does not lie on any side or vertex. Therefore P is an interior point.
Answer: P(3, 2) is in the interior of triangle ABC.

Another Example

This example uses a circle instead of a polygon, showing how 'interior' applies to curved figures and illustrating the key distinction between boundary and interior points.

Problem: A circle has center O(0, 0) and radius r = 5. Determine whether the points Q(3, 4) and R(1, 2) are interior points, boundary points, or exterior points.
Step 1: For any point, compute its distance from the center and compare it to the radius. A point is interior if d < r, on the boundary if d = r, and exterior if d > r.
Step 2: Find the distance from O to Q.
dQ=32+42=9+16=25=5d_Q = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5
Step 3: Since d_Q = r = 5, point Q lies exactly on the circumference. It is a boundary point, NOT an interior point.
Step 4: Find the distance from O to R.
dR=12+22=1+4=52.24d_R = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \approx 2.24
Step 5: Since d_R ≈ 2.24 < 5 = r, point R is strictly inside the circle and is an interior point.
Answer: Q(3, 4) is on the boundary (not interior). R(1, 2) is an interior point of the circle.

Frequently Asked Questions

What is the difference between interior and boundary of a shape?
The boundary consists of the points that form the figure's outline — vertices, sides, edges, circumference, or surface. The interior consists of all points enclosed by that boundary, none of which touch it. Together, the boundary and interior make up the closed region of a figure.
Is a vertex an interior point?
No. A vertex is a corner point where two or more sides or edges meet, so it is part of the boundary. By definition, interior points cannot be vertices or lie on any side, edge, face, or surface of the figure.
How do you tell if a point is in the interior of a polygon?
One common method is the sub-area test: divide the polygon into triangles using the test point and each edge. If the sum of the sub-triangle areas equals the polygon's total area and no sub-area is zero, the point is interior. Another method is the ray-casting test: draw a ray from the point in any direction and count how many times it crosses the polygon's boundary. An odd count means the point is inside.

Interior vs. Boundary

InteriorBoundary
DefinitionAll points strictly enclosed by a figureAll points forming the outline of a figure (sides, edges, vertices, surface)
Includes vertices?NoYes
Includes points on sides/edges?NoYes
Circle examplePoints with distance < r from centerPoints with distance = r from center (the circumference)
Notation (topology)int(F) or F°∂F

Why It Matters

Understanding interior points is essential when working with area, volume, and inequalities in coordinate geometry. Many geometry problems ask you to determine whether a point falls inside, outside, or on a figure — classifying it as interior, exterior, or boundary. The concept also extends to higher math: in topology and real analysis, the interior of a set is a foundational idea used to define open sets.

Common Mistakes

Mistake: Counting points on the boundary (vertices, sides, or circumference) as interior points.
Correction: Interior points are strictly inside the figure. Any point on a side, edge, vertex, or surface is a boundary point, not an interior point.
Mistake: Confusing 'interior' of a figure with 'interior angles' of a polygon.
Correction: The interior of a figure refers to the enclosed region of points. An interior angle is the angle formed between two adjacent sides, measured inside the polygon. These are related but distinct concepts.

Related Terms

  • PointThe fundamental object being classified as interior or not
  • Geometric FigureThe shape whose interior is being identified
  • VertexA boundary point, excluded from the interior
  • Side of a PolygonPart of the boundary enclosing the interior
  • Polygon InteriorInterior concept applied specifically to polygons
  • DiskA circle's interior together with its boundary
  • CircumferenceThe boundary of a circle, not part of its interior
  • Edge of a PolyhedronPart of the boundary of a 3D figure