Problem: A triangle has vertices at A(1, 2), B(5, 2), and C(3, 6). Identify each vertex and count the total number of vertices.
Step 1: A triangle is a polygon with three sides. Each side meets another side at a corner point — that corner point is a vertex.
Step 2: At point A(1, 2), side AB meets side AC. So A is a vertex.
Step 3: At point B(5, 2), side AB meets side BC. So B is a vertex.
Step 4: At point C(3, 6), side AC meets side BC. So C is a vertex.
Step 5: Count the vertices: A, B, and C give a total of 3 vertices. This matches the general rule that an n-sided polygon has n vertices.
Answer: The triangle has 3 vertices: A(1, 2), B(5, 2), and C(3, 6).