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Regular Pyramid

Regular Pyramid

A pyramid with a base that is a regular polygon. The apex is not necessarily directly above the center of the base.

Note: For some mathematicians regular pyramid means the same as right regular pyramid.

Solid view of a right regular pyramid with a regular pentagon base, shown in yellow-green with shaded lateral faces tapering...
Solid view: regular pyramid with a regular pentagon as base
Solid view of a right regular pyramid with a pentagonal base and red vertical height labeled h from apex to base.
Frame view: regular pyramid with a regular pentagon as base
Volume = (1/3)(area of base)(height)
h = height of the pyramid
B = area of the base

 

See also

Right pyramid, volume, area of a regular polygon

Key Formula

V=13BhV = \frac{1}{3}Bh
Where:
  • VV = Volume of the pyramid
  • BB = Area of the regular polygon base
  • hh = Perpendicular height from the base to the apex (altitude of the pyramid)

Worked Example

Problem: A regular pyramid has a square base with side length 6 cm and a height of 10 cm. Find its volume.
Step 1: Identify the base shape. The base is a square with side length 6 cm, which is a regular polygon (all four sides equal, all angles 90°).
Step 2: Calculate the area of the square base.
B=s2=62=36 cm2B = s^2 = 6^2 = 36 \text{ cm}^2
Step 3: Apply the pyramid volume formula using the base area and the given height.
V=13Bh=13(36)(10)V = \frac{1}{3}Bh = \frac{1}{3}(36)(10)
Step 4: Compute the volume.
V=3603=120 cm3V = \frac{360}{3} = 120 \text{ cm}^3
Answer: The volume of the regular pyramid is 120 cm³.

Another Example

This example uses a hexagonal base instead of a square, showing how you need the area formula for a different regular polygon before applying the same volume formula.

Problem: A regular pyramid has a regular hexagonal base with side length 4 cm and a height of 9 cm. Find its volume.
Step 1: Recall the area formula for a regular hexagon with side length s.
B=332s2B = \frac{3\sqrt{3}}{2}\,s^2
Step 2: Substitute s = 4 cm into the hexagon area formula.
B=332(4)2=332(16)=243 cm2B = \frac{3\sqrt{3}}{2}(4)^2 = \frac{3\sqrt{3}}{2}(16) = 24\sqrt{3} \text{ cm}^2
Step 3: Apply the pyramid volume formula with h = 9 cm.
V=13Bh=13(243)(9)=723 cm3V = \frac{1}{3}Bh = \frac{1}{3}(24\sqrt{3})(9) = 72\sqrt{3} \text{ cm}^3
Step 4: Approximate the result if needed.
V72(1.732)124.7 cm3V \approx 72(1.732) \approx 124.7 \text{ cm}^3
Answer: The volume is 723124.772\sqrt{3} \approx 124.7 cm³.

Frequently Asked Questions

What is the difference between a regular pyramid and a right regular pyramid?
A regular pyramid only requires that the base is a regular polygon. A right regular pyramid additionally requires that the apex lies directly above the center of the base, so the altitude drops perpendicularly to the centroid. Many textbooks treat these terms as synonymous, but strictly a regular pyramid can be oblique (tilted) as long as the base is regular.
How do you find the surface area of a regular pyramid?
For a right regular pyramid, the total surface area is the base area plus the lateral area. The lateral area equals 12Pl\frac{1}{2}Pl, where PP is the perimeter of the base and ll is the slant height. So the total surface area is SA=B+12PlSA = B + \frac{1}{2}Pl. If the pyramid is oblique, each lateral face may have a different area and must be calculated individually.
Can a triangle be the base of a regular pyramid?
Yes. If the base is an equilateral triangle (which is a regular polygon with three equal sides), the pyramid is a regular pyramid. A regular pyramid with an equilateral triangular base where all four faces are equilateral triangles is called a regular tetrahedron.

Regular Pyramid vs. Right Regular Pyramid

Regular PyramidRight Regular Pyramid
Base requirementMust be a regular polygonMust be a regular polygon
Apex positionCan be anywhere above or beside the baseMust be directly above the center of the base
Lateral facesTriangles (not necessarily congruent)Congruent isosceles triangles
Volume formulaV = (1/3)BhV = (1/3)Bh
Slant heightMay differ for each faceSame for all lateral faces

Why It Matters

Regular pyramids appear frequently in geometry courses when studying three-dimensional solids, surface area, and volume. They also show up in real-world structures—the Great Pyramid of Giza, for instance, has a nearly square (regular polygon) base. Understanding how the base shape affects formulas for area and volume is a key skill tested in standardized exams.

Common Mistakes

Mistake: Confusing height (h) with slant height (l).
Correction: The height h is the perpendicular distance from the base to the apex, measured inside the pyramid. The slant height l runs along a lateral face from the apex to the midpoint of a base edge. Using slant height in the volume formula gives the wrong answer. For volume, always use the perpendicular height.
Mistake: Assuming every regular pyramid is also a right pyramid.
Correction: A regular pyramid only requires a regular polygon base. The apex does not have to be centered above the base. If a problem says 'regular pyramid,' check whether the apex is centered before using slant-height shortcuts that assume congruent lateral faces.

Related Terms