Mathwords logoMathwords

Thales' Theorem — Definition, Formula & Examples

Thales' Theorem states that if you draw a triangle inside a circle where one side is the diameter, the angle opposite that diameter is always 90°. In other words, any angle inscribed in a semicircle is a right angle.

Let ABAB be a diameter of a circle with center OO, and let CC be any point on the circle distinct from AA and BB. Then ACB=90°\angle ACB = 90°. This is a special case of the inscribed angle theorem, where the intercepted arc is a semicircle of measure 180°180°.

Key Formula

ACB=12×180°=90°\angle ACB = \frac{1}{2} \times 180° = 90°
Where:
  • A,BA, B = Endpoints of a diameter of the circle
  • CC = Any other point on the circle
  • ACB\angle ACB = The inscribed angle opposite the diameter

How It Works

Pick any diameter ABAB of a circle. Choose any point CC on the circle (not at AA or BB) and connect CC to both AA and BB. The resulting triangle ABCABC always has a right angle at CC. This works because the inscribed angle ACB\angle ACB intercepts an arc of 180°180°, and an inscribed angle is half its intercepted arc, giving 180°2=90°\frac{180°}{2} = 90°. The converse also holds: if ACB=90°\angle ACB = 90°, then ABAB must be a diameter of the circle passing through AA, BB, and CC.

Worked Example

Problem: A circle has center O and diameter AB = 10 cm. Point C lies on the circle such that AC = 6 cm. Find the length of BC.
Apply Thales' Theorem: Since AB is a diameter and C is on the circle, Thales' Theorem tells us that angle ACB is 90°.
ACB=90°\angle ACB = 90°
Use the Pythagorean Theorem: Triangle ACB is right-angled at C, so AB is the hypotenuse.
AB2=AC2+BC2AB^2 = AC^2 + BC^2
Solve for BC: Substitute the known values and solve.
102=62+BC2    100=36+BC2    BC2=64    BC=8 cm10^2 = 6^2 + BC^2 \implies 100 = 36 + BC^2 \implies BC^2 = 64 \implies BC = 8 \text{ cm}
Answer: BC = 8 cm

Why It Matters

Thales' Theorem gives you a reliable way to construct a right angle using only a compass and straightedge, which is fundamental in geometric constructions. It appears frequently in high school geometry proofs involving cyclic quadrilaterals and circle theorems, and it is used in engineering and surveying to verify perpendicularity.

Common Mistakes

Mistake: Assuming any chord (not just a diameter) creates a 90° inscribed angle.
Correction: The inscribed angle is 90° only when the opposite side is a diameter. For other chords, the inscribed angle equals half the intercepted arc, which will not be 90° unless that arc is exactly 180°.