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Neighborhood

Neighborhood

A neighborhood of a number a is any open interval containing a. One common notation for a neighborhood of a is {x: |xa| < δ}. Using interval notation this would be (a – δ, a + δ).

 

 

See also

Deleted neighborhood, set-builder notation, Greek alphabet, set

Key Formula

Nδ(a)={x:xa<δ}=(aδ,  a+δ)N_\delta(a) = \{ x : |x - a| < \delta \} = (a - \delta,\; a + \delta)
Where:
  • aa = The center point of the neighborhood
  • δ\delta = A positive real number giving the radius (half-width) of the neighborhood
  • xx = Any point that belongs to the neighborhood

Worked Example

Problem: Describe the neighborhood of radius 0.5 centered at 3, and determine whether the points 2.8, 3.6, and 3.5 belong to it.
Step 1: Write the neighborhood using the definition with a=3a = 3 and δ=0.5\delta = 0.5.
N0.5(3)={x:x3<0.5}=(2.5,  3.5)N_{0.5}(3) = \{ x : |x - 3| < 0.5 \} = (2.5,\; 3.5)
Step 2: Check x=2.8x = 2.8: compute 2.83=0.2|2.8 - 3| = 0.2. Since 0.2<0.50.2 < 0.5, the point 2.8 is inside the neighborhood.
2.83=0.2<0.5  |2.8 - 3| = 0.2 < 0.5 \;\checkmark
Step 3: Check x=3.6x = 3.6: compute 3.63=0.6|3.6 - 3| = 0.6. Since 0.6>0.50.6 > 0.5, the point 3.6 is outside the neighborhood.
3.63=0.60.5|3.6 - 3| = 0.6 \not< 0.5
Step 4: Check x=3.5x = 3.5: compute 3.53=0.5|3.5 - 3| = 0.5. Since 0.50.5 is not strictly less than 0.50.5, the endpoint 3.5 is not inside the neighborhood. The neighborhood is an open interval, so its endpoints are excluded.
3.53=0.50.5|3.5 - 3| = 0.5 \not< 0.5
Answer: The neighborhood is the open interval (2.5,3.5)(2.5, 3.5). The point 2.8 belongs to it, while 3.6 and 3.5 do not.

Frequently Asked Questions

What is the difference between a neighborhood and a deleted neighborhood?
A neighborhood of aa includes the center point aa itself: (aδ,a+δ)(a - \delta, a + \delta). A deleted neighborhood removes the center point, giving (aδ,a)(a,a+δ)(a - \delta, a) \cup (a, a + \delta), or equivalently {x:0<xa<δ}\{x : 0 < |x - a| < \delta\}. Deleted neighborhoods are used when you want to examine behavior near aa without considering the value at aa itself, which is exactly the situation in the definition of a limit.
Why does a neighborhood have to be an open interval?
Openness ensures that every point in the neighborhood has some breathing room around it — no point sits on a boundary. This property is essential for definitions in calculus and analysis, such as limits and continuity, where you need to get arbitrarily close to a point from both sides without hitting an edge.

Neighborhood vs. Deleted Neighborhood

A neighborhood Nδ(a)=(aδ,a+δ)N_\delta(a) = (a - \delta, a + \delta) contains the center point aa. A deleted neighborhood Nδ(a)={x:0<xa<δ}N_\delta^*(a) = \{x : 0 < |x - a| < \delta\} is the same set with aa removed. You use a deleted neighborhood when defining limits, because the limit of f(x)f(x) as xax \to a depends on values near aa but not at aa itself.

Why It Matters

Neighborhoods are the building blocks of the formal ε\varepsilon-δ\delta definitions of limits and continuity in calculus. When you read "for every ε>0\varepsilon > 0 there exists a δ>0\delta > 0…," the statement is describing neighborhoods of specific sizes around points. Without the concept of a neighborhood, you cannot make rigorous statements about what happens "close to" a given number.

Common Mistakes

Mistake: Including the endpoints: writing [aδ,a+δ][a - \delta, a + \delta] instead of (aδ,a+δ)(a - \delta, a + \delta).
Correction: A neighborhood is an open interval, so the boundary points aδa - \delta and a+δa + \delta are excluded. Points at exactly distance δ\delta from aa are not in the neighborhood.
Mistake: Confusing a neighborhood with a deleted neighborhood and excluding the center point aa.
Correction: A standard neighborhood includes aa. Only a deleted neighborhood removes aa. Be careful about which one a definition calls for — limits use deleted neighborhoods, while continuity checks use ordinary neighborhoods.

Related Terms