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Continuity at a Point

Continuity at a point means that a function has no breaks, jumps, or holes at that specific xx-value. For a function to be continuous at a point, it must be defined there, its limit must exist there, and the limit must equal the function's value.

A function ff is continuous at a point x=cx = c if three conditions are all satisfied: (1) f(c)f(c) is defined, (2) limxcf(x)\lim_{x \to c} f(x) exists, and (3) limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c). If any one of these conditions fails, the function is discontinuous at x=cx = c. This definition captures the intuitive idea that you can draw the graph through the point without lifting your pen.

Key Formula

limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c)
Where:
  • ff = the function being tested for continuity
  • cc = the specific x-value (point) where continuity is being checked
  • f(c)f(c) = the value of the function at x = c

Worked Example

Problem: Determine whether f(x)=x24x2f(x) = \frac{x^2 - 4}{x - 2} is continuous at x=2x = 2.
Step 1 — Check if f(2) is defined: Substitute x=2x = 2 into the function.
f(2)=22422=00f(2) = \frac{2^2 - 4}{2 - 2} = \frac{0}{0}
Step 2 — Conclude from Condition 1: f(2)f(2) is undefined because we get division by zero. Since the first condition already fails, the function is not continuous at x=2x = 2.
Step 3 — Investigate the limit anyway: Factor the numerator to see what the limit would be, which helps you understand the type of discontinuity.
limx2x24x2=limx2(x2)(x+2)x2=limx2(x+2)=4\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} \frac{(x-2)(x+2)}{x-2} = \lim_{x \to 2}(x+2) = 4
Step 4 — Identify the discontinuity type: The limit exists and equals 4, but f(2)f(2) is undefined. This means there is a removable discontinuity (a hole) at x=2x = 2. If we redefined f(2)=4f(2) = 4, the function would become continuous there.
Answer: f(x)f(x) is not continuous at x=2x = 2 because f(2)f(2) is undefined, even though the limit exists.

Why It Matters

Continuity at a point is foundational to calculus. Many key theorems — including the Intermediate Value Theorem and the rules for differentiation — require functions to be continuous. When you check differentiability at a point or evaluate a definite integral, continuity is often the first thing you need to verify.

Common Mistakes

Mistake: Checking only whether the limit exists and forgetting to verify that the function is actually defined at the point.
Correction: All three conditions must hold. A function can have a limit at x=cx = c but still be discontinuous there if f(c)f(c) is undefined or doesn't match the limit.
Mistake: Assuming a function is continuous just because you can compute f(c)f(c) and get a number.
Correction: You also need the limit to exist and equal f(c)f(c). Piecewise functions, for example, can be defined at a point yet have a jump where the left- and right-hand limits disagree.

Related Terms

  • Continuous FunctionContinuous everywhere vs. at a single point
  • DiscontinuityWhat occurs when continuity conditions fail
  • LimitCentral requirement in the continuity definition