Mathwords logoMathwords

Limit from the Right — Definition, Formula & Examples

Limit from the Right
Limit from Above

A one-sided limit which, in the example lim⁡x→0+1x=∞,\displaystyle \lim_{x \to 0^+}\frac{1}{x} = \infty\text{,} restricts x such that x > 0.

In general, a limit from the right restricts domain variable to values greater than the number the domain variable approaches. When a limit is taken from the right it is written lim⁡x→a+f(x)\displaystyle \lim_{x \to a^+} f(x) or lim⁡x↓af(x).\displaystyle \lim_{x \downarrow a} f(x)\text{.}

For example, lim⁡x→0+1x=∞\displaystyle \lim_{x \to 0^+}\frac{1}{x} = \infty since 1x\displaystyle \frac{1}{x} tends toward ∞ as x gets closer and closer to 0 from the right.

Formal Definitions:

1. lim⁡x→a+f(x)=L\displaystyle \lim_{x\to a^+} f(x) = L if and only if for each ε>0\varepsilon \gt 0 there exists a δ>0\delta \gt 0 such that
  a<x<a+δ⇒∣f(x)−L∣<ε.a \lt x \lt a + \delta \Rightarrow |f(x)-L| \lt \varepsilon\text{.}

2. lim⁡x→a+f(x)=∞\displaystyle \lim_{x\to a^+} f(x) = \infty if and only if for each NN there exists a δ>0\delta \gt 0 such that
  a<x<a+δ⇒f(x)>N.a \lt x \lt a + \delta \Rightarrow f(x) \gt N\text{.}

3. lim⁡x→a+f(x)=−∞\displaystyle \lim_{x\to a^+} f(x) = -\infty if and only if for each NN there exists a δ>0\delta \gt 0 such that
  a<x<a+δ⇒f(x)<N.a \lt x \lt a + \delta \Rightarrow f(x) \lt N\text{.}

See also

Limit from the left, infinity

Key Formula

lim⁡x→c+f(x)=L\lim_{x \to c^+} f(x) = L
Where:
  • xx = The input (domain) variable approaching the value c
  • cc = The number that x approaches, from values greater than c
  • f(x)f(x) = The function being evaluated
  • LL = The value the function approaches (the limit)
  • ++ = The superscript plus sign indicates the approach is from the right (values greater than c)

Worked Example

Problem: Find the limit from the right: lim⁡x→0+1x\lim_{x \to 0^+} \frac{1}{x}
Step 1: Identify the point of approach and the direction. Here, x approaches 0 from the right, meaning x takes positive values close to 0.
x→0+meansx=0.1,  0.01,  0.001,…x \to 0^+ \quad \text{means} \quad x = 0.1,\; 0.01,\; 0.001, \ldots
Step 2: Evaluate the function at values approaching 0 from the right.
f(0.1)=10.1=10,f(0.01)=100,f(0.001)=1000f(0.1) = \frac{1}{0.1} = 10, \quad f(0.01) = 100, \quad f(0.001) = 1000
Step 3: Observe the trend. As x gets closer to 0 from the right, the output grows without bound.
1x→+∞asx→0+\frac{1}{x} \to +\infty \quad \text{as} \quad x \to 0^+
Step 4: State the result. The function increases without limit, so we say the right-hand limit is positive infinity.
lim⁡x→0+1x=+∞\lim_{x \to 0^+} \frac{1}{x} = +\infty
Answer: lim⁡x→0+1x=+∞\lim_{x \to 0^+} \frac{1}{x} = +\infty. The function grows without bound as xx approaches 0 from the right.

Another Example

This example shows a case where the function is only defined on one side of the point. A limit from the left does not exist here because x−2\sqrt{x-2} is undefined for x<2x < 2. The right-hand limit is the only one-sided limit that makes sense at this endpoint.

Problem: Find the limit from the right: lim⁡x→2+x−2\lim_{x \to 2^+} \sqrt{x - 2}
Step 1: Identify the point and direction. We approach x = 2 from values greater than 2, so x > 2.
x→2+meansx=2.1,  2.01,  2.001,…x \to 2^+ \quad \text{means} \quad x = 2.1,\; 2.01,\; 2.001, \ldots
Step 2: Check the domain. The square root function x−2\sqrt{x-2} is only defined when x−2≥0x - 2 \geq 0, i.e., x≥2x \geq 2. So the function only exists on the right side of 2.
Domain: x≥2\text{Domain: } x \geq 2
Step 3: Evaluate the function at values approaching 2 from the right.
f(2.1)=0.1≈0.316,f(2.01)=0.01=0.1,f(2.001)=0.001≈0.0316f(2.1) = \sqrt{0.1} \approx 0.316, \quad f(2.01) = \sqrt{0.01} = 0.1, \quad f(2.001) = \sqrt{0.001} \approx 0.0316
Step 4: As x approaches 2 from the right, the expression inside the square root approaches 0, so the output approaches 0.
lim⁡x→2+x−2=0=0\lim_{x \to 2^+} \sqrt{x - 2} = \sqrt{0} = 0
Answer: lim⁡x→2+x−2=0\lim_{x \to 2^+} \sqrt{x - 2} = 0

Frequently Asked Questions

What is the difference between a limit from the right and a limit from the left?
A limit from the right (lim⁡x→c+\lim_{x \to c^+}) only considers values of xx that are greater than cc, while a limit from the left (lim⁡x→c−\lim_{x \to c^-}) only considers values less than cc. If both one-sided limits exist and are equal, the two-sided limit lim⁡x→cf(x)\lim_{x \to c} f(x) exists and equals that common value. If they differ, the two-sided limit does not exist.
When do you need to use the limit from the right?
You use the limit from the right when a function behaves differently on either side of a point, such as piecewise functions or functions with vertical asymptotes. It is also essential when the function is only defined for values greater than or equal to the point, like x\sqrt{x} at x=0x = 0. Right-hand limits appear frequently when analyzing continuity and when determining whether a two-sided limit exists.
What does the plus sign mean in lim⁡x→c+\lim_{x \to c^+}?
The superscript plus sign (++) indicates the direction of approach. It means xx approaches cc from values greater than cc—that is, from the right side on a number line. This notation is sometimes also written as lim⁡x↓c\lim_{x \downarrow c} or lim⁡x→c+\lim_{x \to c+} without the superscript, though the c+c^+ form is most common in textbooks.

Limit from the Right vs. Limit from the Left

Limit from the RightLimit from the Left
Notationlim⁡x→c+f(x)\lim_{x \to c^+} f(x)lim⁡x→c−f(x)\lim_{x \to c^-} f(x)
Direction of approachx approaches c from values greater than cx approaches c from values less than c
Restriction on xx > cx < c
Also calledRight-hand limit, limit from aboveLeft-hand limit, limit from below
Example: lim⁡1/x\lim 1/x as x→0x \to 0+∞+\infty−∞-\infty

Why It Matters

Right-hand limits appear constantly in calculus courses when you study continuity, derivatives, and the behavior of functions near discontinuities or domain boundaries. For piecewise-defined functions, you must check both one-sided limits to determine whether the overall limit exists at a boundary point. Understanding right-hand limits is also critical for analyzing vertical asymptotes, improper integrals, and the convergence of sequences and series.

Common Mistakes

Mistake: Confusing the direction: thinking x→c+x \to c^+ means x approaches from the left (smaller values).
Correction: The plus sign means x approaches c from values greater than c (the right side on a number line). Think of it as x = c + a tiny positive amount that shrinks to zero.
Mistake: Assuming that if the right-hand limit exists, the two-sided limit must also exist.
Correction: The two-sided limit exists only if both the right-hand and left-hand limits exist and are equal. For example, lim⁡x→0+1x=+∞\lim_{x \to 0^+} \frac{1}{x} = +\infty and lim⁡x→0−1x=−∞\lim_{x \to 0^-} \frac{1}{x} = -\infty, so lim⁡x→01x\lim_{x \to 0} \frac{1}{x} does not exist.

Related Terms

  • One-Sided Limit — General category that includes right-hand limits
  • Limit from the Left — The other one-sided limit, approaching from below
  • Domain — Right-hand limits restrict the domain to x > c
  • Variable — The input variable x whose approach direction is restricted
  • Infinity — Right-hand limits can equal positive or negative infinity
  • Continuous — Continuity requires one-sided limits to agree
  • Piecewise Function — Often requires separate one-sided limits at boundaries