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Fixed Point Theorem — Definition, Formula & Examples

A fixed point theorem guarantees that under certain conditions, a function has at least one fixed point — a value cc where f(c)=cf(c) = c. The most common version in introductory calculus states that any continuous function mapping a closed interval to itself must have a fixed point.

Let f:[a,b][a,b]f: [a, b] \to [a, b] be continuous. Then there exists at least one point c[a,b]c \in [a, b] such that f(c)=cf(c) = c. This result follows directly from the Intermediate Value Theorem applied to the auxiliary function g(x)=f(x)xg(x) = f(x) - x.

Key Formula

g(x)=f(x)x=0    f(c)=cg(x) = f(x) - x = 0 \implies f(c) = c
Where:
  • ff = A continuous function mapping [a, b] into [a, b]
  • cc = The fixed point where the function's output equals its input
  • g(x)g(x) = Auxiliary function used to apply the Intermediate Value Theorem

How It Works

To prove a fixed point exists, define g(x)=f(x)xg(x) = f(x) - x. Since ff maps [a,b][a, b] into [a,b][a, b], you know f(a)af(a) \geq a, so g(a)0g(a) \geq 0, and f(b)bf(b) \leq b, so g(b)0g(b) \leq 0. Because gg is continuous and changes sign on [a,b][a, b], the Intermediate Value Theorem guarantees some cc where g(c)=0g(c) = 0, meaning f(c)=cf(c) = c. To actually find a fixed point numerically, you can iterate: pick a starting value x0x_0 and compute x1=f(x0)x_1 = f(x_0), x2=f(x1)x_2 = f(x_1), and so on, hoping the sequence converges.

Worked Example

Problem: Show that f(x) = cos(x) has a fixed point on [0, 1], and estimate it.
Step 1: Verify that f maps [0, 1] into [0, 1]. We have cos(0) = 1 and cos(1) ≈ 0.5403, and cosine is decreasing on this interval, so all outputs lie in [0.5403, 1] ⊂ [0, 1].
f(0)=1,f(1)0.5403f(0) = 1, \quad f(1) \approx 0.5403
Step 2: Define g(x) = cos(x) − x and check the sign at the endpoints.
g(0)=10=1>0,g(1)0.54031=0.4597<0g(0) = 1 - 0 = 1 > 0, \quad g(1) \approx 0.5403 - 1 = -0.4597 < 0
Step 3: Since g is continuous and changes sign on [0, 1], the Intermediate Value Theorem guarantees a root c where g(c) = 0, i.e., cos(c) = c.
c0.7391c \approx 0.7391
Answer: The function f(x) = cos(x) has a fixed point at approximately c ≈ 0.7391, known as the Dottie number.

Why It Matters

Fixed point theorems appear throughout mathematics and applied sciences. In numerical analysis, fixed-point iteration is a standard method for solving equations. Brouwer's Fixed Point Theorem, a generalization to higher dimensions, underpins proofs in economics (Nash equilibrium) and differential equations (existence of solutions).

Common Mistakes

Mistake: Assuming every continuous function has a fixed point, regardless of domain.
Correction: The theorem requires that f maps a closed interval (or more generally, a compact convex set) into itself. For example, f(x) = x + 1 on all of ℝ is continuous but has no fixed point.