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Tautochrone

Tautochrone

A cycloid hanging downwards.

Note: Tautochrone is a term from Greek meaning "the same time." The special property of a tautochrone is the fact that a bead sliding down a tautochrone-shaped frictionless wire will take the same amount of time to reach the bottom no matter how high or low the release point. In fact, since a tautochrone is also a brachistochrone, the bead will take the shortest possible time to reach the bottom out of all possible shapes of the wire.

 

Movie clip

Upside-down cycloid curve on a grid (x: 0–6, y: –2 to 0), with colored beads at different heights, all reaching the bottom in...
Tautochrone--sliding
beads on a cycloid

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Key Formula

T=πrgT = \pi \sqrt{\frac{r}{g}}
Where:
  • TT = Time for the bead to slide from any starting point to the bottom of the cycloid
  • rr = Radius of the generating circle that defines the cycloid
  • gg = Acceleration due to gravity (approximately 9.8 m/s²)

Worked Example

Problem: A frictionless wire is bent into the shape of an inverted cycloid generated by a circle of radius r = 1 meter. Two beads are released from rest: one near the top of the curve and one from a point only slightly above the bottom. How long does each bead take to reach the lowest point? Use g = 9.8 m/s².
Step 1: Identify the tautochrone property. The descent time is the same for every starting point on the cycloid, so both beads take the same time.
Step 2: Write the formula for the descent time on a tautochrone cycloid with generating-circle radius r.
T=πrgT = \pi \sqrt{\frac{r}{g}}
Step 3: Substitute r = 1 m and g = 9.8 m/s².
T=π19.8=π0.10204π×0.3194T = \pi \sqrt{\frac{1}{9.8}} = \pi \sqrt{0.10204} \approx \pi \times 0.3194
Step 4: Compute the numerical result.
T3.1416×0.31941.003 secondsT \approx 3.1416 \times 0.3194 \approx 1.003 \text{ seconds}
Answer: Both beads reach the bottom in approximately 1.00 seconds, illustrating the tautochrone property: the descent time is independent of the release point.

Frequently Asked Questions

Why does a tautochrone have the equal-time property?
A bead released from higher up has farther to travel, but the steeper initial slope accelerates it more quickly. A bead released from lower down travels a shorter distance but accelerates more slowly on the gentler slope. On a cycloid, these two effects balance perfectly, so every starting height yields the same total descent time. Christiaan Huygens proved this result in 1673 using the theory of evolutes.
Is a tautochrone the same as a brachistochrone?
Both curves turn out to be cycloids, but they answer different questions. The brachistochrone is the curve of fastest descent between two fixed points; the tautochrone is the curve on which descent time is the same from any starting point. It is a remarkable coincidence that both problems are solved by the same family of curves.

Tautochrone vs. Brachistochrone

A tautochrone is the curve on which all frictionless descents under gravity take equal time regardless of start position. A brachistochrone is the curve giving the shortest possible descent time between two specific points. Both are cycloids, but they address fundamentally different optimization questions — equal time versus least time.

Why It Matters

The tautochrone problem, solved by Huygens in 1673, led him to design a pendulum clock with cycloid-shaped cheeks that kept nearly perfect time regardless of the swing amplitude. This was one of the first practical applications of higher mathematics to engineering. The problem also helped motivate the development of the calculus of variations, a branch of mathematics used throughout physics and engineering today.

Common Mistakes

Mistake: Assuming a straight ramp (inclined plane) has the equal-time property.
Correction: On a straight ramp, a bead released from higher up takes longer to reach the bottom. Only the cycloid shape guarantees equal descent time from every starting height.
Mistake: Confusing the tautochrone condition with the brachistochrone condition as if they ask the same question.
Correction: The tautochrone asks: on what curve is descent time independent of start position? The brachistochrone asks: what curve minimizes descent time between two fixed points? They happen to share the same answer (cycloid), but the problems are distinct.

Related Terms