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Symmetric

Key Formula

Symmetric w.r.t. the y-axis: f(x)=f(x)for all x\text{Symmetric w.r.t. the } y\text{-axis: } f(x) = f(-x) \quad \text{for all } x Symmetric w.r.t. the origin: f(x)=f(x)for all x\text{Symmetric w.r.t. the origin: } f(-x) = -f(x) \quad \text{for all } x Symmetric w.r.t. the x-axis: if (x,y) is on the graph, then (x,y) is also on the graph\text{Symmetric w.r.t. the } x\text{-axis: if } (x, y) \text{ is on the graph, then } (x, -y) \text{ is also on the graph}
Where:
  • f(x)f(x) = The function or equation being tested for symmetry
  • xx = Any input value in the domain
  • yy = The output or vertical coordinate
  • x-x = The opposite of the input, used to test reflection across the y-axis or origin
  • y-y = The opposite of the output, used to test reflection across the x-axis

Worked Example

Problem: Determine whether the graph of f(x) = x² + 4 is symmetric with respect to the y-axis.
Step 1: Write the symmetry test for the y-axis. A graph is symmetric about the y-axis if f(-x) = f(x) for every x.
Test: f(x)=f(x)?\text{Test: } f(-x) = f(x)\,?
Step 2: Compute f(-x) by replacing every x in the formula with -x.
f(x)=(x)2+4=x2+4f(-x) = (-x)^2 + 4 = x^2 + 4
Step 3: Compare f(-x) with the original f(x).
f(x)=x2+4=f(x)f(-x) = x^2 + 4 = f(x)
Step 4: Since f(-x) equals f(x) for all x, the condition is satisfied.
Answer: Yes, f(x) = x² + 4 is symmetric with respect to the y-axis. Its graph is a parabola opening upward, and the y-axis is its axis of symmetry.

Another Example

This example differs from the first because it tests an equation (not a function) for all three types of symmetry. A circle is a rare case where all three hold simultaneously. Note that this relation is not a function because it fails the vertical line test, yet x-axis symmetry still applies.

Problem: Determine all types of symmetry for the equation x² + y² = 25.
Step 1: Test for y-axis symmetry by replacing x with -x and checking whether the equation is unchanged.
(x)2+y2=x2+y2=25(-x)^2 + y^2 = x^2 + y^2 = 25 \quad \checkmark
Step 2: Test for x-axis symmetry by replacing y with -y.
x2+(y)2=x2+y2=25x^2 + (-y)^2 = x^2 + y^2 = 25 \quad \checkmark
Step 3: Test for origin symmetry by replacing both x with -x and y with -y.
(x)2+(y)2=x2+y2=25(-x)^2 + (-y)^2 = x^2 + y^2 = 25 \quad \checkmark
Step 4: All three substitutions produce the original equation, so the graph has all three types of symmetry.
Answer: The circle x² + y² = 25 is symmetric with respect to the y-axis, the x-axis, and the origin.

Frequently Asked Questions

How do you test if a graph is symmetric?
You use algebraic substitution. Replace x with -x to test y-axis symmetry, replace y with -y to test x-axis symmetry, or replace both x with -x and y with -y to test origin symmetry. If the resulting equation is equivalent to the original, that type of symmetry exists.
What is the difference between symmetric about the y-axis and symmetric about the origin?
Y-axis symmetry means the left half of the graph mirrors the right half across the y-axis; algebraically, f(-x) = f(x). These are called even functions. Origin symmetry means rotating the graph 180° about the origin leaves it unchanged; algebraically, f(-x) = -f(x). These are called odd functions. A graph cannot be both unless it is the constant function f(x) = 0.
Can a function be symmetric about the x-axis?
No. If a graph is symmetric about the x-axis, then for some x-value there would be two y-values (y and -y), which violates the definition of a function. Only relations that are not functions—such as circles or horizontal parabolas like x = y²—can have x-axis symmetry.

Y-axis symmetry (even function) vs. Origin symmetry (odd function)

Y-axis symmetry (even function)Origin symmetry (odd function)
Algebraic testf(-x) = f(x)f(-x) = -f(x)
Geometric meaningLeft side mirrors right side across the y-axisGraph looks the same after a 180° rotation about the origin
Classic examplesx², cos(x), |x|x³, sin(x), 1/x
Graph behavior at originNot required to pass through originMust pass through the origin (if defined there)
Alternate nameEven functionOdd function

Why It Matters

Symmetry simplifies graphing because you only need to plot half the graph and reflect. In calculus, knowing a function is even lets you write aaf(x)dx=20af(x)dx\int_{-a}^{a} f(x)\,dx = 2\int_{0}^{a} f(x)\,dx, while knowing it is odd means the integral over a symmetric interval equals zero. Symmetry also appears throughout physics, engineering, and art whenever balanced or mirror-image structures arise.

Common Mistakes

Mistake: Assuming that because a graph looks symmetric, it must satisfy the algebraic test.
Correction: Always verify symmetry algebraically. For example, y = x² + x looks nearly symmetric near its vertex but fails the test f(-x) ≠ f(x), so it is not symmetric about the y-axis.
Mistake: Confusing origin symmetry with y-axis symmetry when testing f(-x).
Correction: After computing f(-x), compare it to both f(x) and -f(x). If f(-x) = f(x), you have y-axis symmetry. If f(-x) = -f(x), you have origin symmetry. These are two different outcomes of the same substitution.

Related Terms