diagonals of a rhombus — Definition, Formula & Examples
The diagonals of a rhombus are the two line segments connecting opposite vertices. They always cross at right angles and cut each other exactly in half.
In a rhombus with vertices , , , , the diagonals and are perpendicular bisectors of each other. If their lengths are and , the intersection point divides each diagonal into two equal segments of length and , respectively.
Key Formula
Where:
- = Area of the rhombus
- = Length of one diagonal
- = Length of the other diagonal
How It Works
Because all four sides of a rhombus are equal, each diagonal splits the rhombus into two congruent isosceles triangles. The two diagonals together split it into four congruent right triangles. At the center, the diagonals meet at , and each half-diagonal and a side form a right triangle you can solve with the Pythagorean theorem. This perpendicular-bisector property is also the reason the area of a rhombus equals half the product of its diagonals.
Worked Example
Problem: A rhombus has diagonals of length 10 cm and 24 cm. Find the side length and the area.
Find the half-diagonals: The diagonals bisect each other, so the half-lengths are 5 cm and 12 cm.
Use the Pythagorean theorem for the side: Each side is the hypotenuse of a right triangle formed by the two half-diagonals.
Calculate the area: Apply the diagonal-based area formula.
Answer: The side length is 13 cm and the area is 120 cm².
Why It Matters
The perpendicular-bisector property shows up in coordinate geometry proofs and in engineering contexts where diamond-shaped cross-sections appear. In courses like geometry and precalculus, you will use it to derive side lengths, angles, and areas without needing trigonometry.
Common Mistakes
Mistake: Assuming the diagonals of a rhombus are equal in length.
Correction: The diagonals are equal only if the rhombus is also a square. In a general rhombus the two diagonals have different lengths.
