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Cone Angle

Cone Angle

The angle remaining in a sheet of paper after a sector has been cut out so that the paper can be rolled into a right circular cone.

 

Three diagrams: a flat sector with "cone angle" labeled, the sector being rolled, and the resulting right circular cone.

 

 

See also

Takeout angle

Key Formula

θcone=360°θtakeout=2πrR×180°π=360°rR\theta_{\text{cone}} = 360° - \theta_{\text{takeout}} = \frac{2\pi r}{R} \times \frac{180°}{\pi} = \frac{360° \, r}{R}
Where:
  • θcone\theta_{\text{cone}} = Cone angle — the central angle of the remaining sector (in degrees)
  • θtakeout\theta_{\text{takeout}} = Takeout angle — the central angle of the sector that was removed (in degrees)
  • rr = Radius of the base of the resulting right circular cone
  • RR = Slant height of the cone, which equals the radius of the original flat disk

Worked Example

Problem: A flat circular disk has radius 10 cm. A sector is cut out so that the remaining piece can be rolled into a right circular cone whose base has radius 6 cm. Find the cone angle.
Step 1: Identify the values. The slant height of the cone equals the radius of the original disk, so R = 10 cm. The base radius of the cone is r = 6 cm.
R=10 cm,r=6 cmR = 10 \text{ cm}, \quad r = 6 \text{ cm}
Step 2: Apply the cone angle formula. The arc length of the remaining sector must equal the circumference of the cone's base, which gives the relationship below.
θcone=360°×rR=360°×610\theta_{\text{cone}} = \frac{360° \times r}{R} = \frac{360° \times 6}{10}
Step 3: Calculate the cone angle.
θcone=2160°10=216°\theta_{\text{cone}} = \frac{2160°}{10} = 216°
Step 4: Find the takeout angle as a check.
θtakeout=360°216°=144°\theta_{\text{takeout}} = 360° - 216° = 144°
Answer: The cone angle is 216°. The removed sector (takeout angle) is 144°.

Another Example

This example explores the boundary case where r = R, illustrating that the formula has a geometric constraint: the base radius must be strictly less than the slant height for a valid cone.

Problem: You want to construct a right circular cone with a base radius of 5 cm and a slant height of 5 cm. What cone angle do you need, and what does the resulting cone look like?
Step 1: Note the given values: r = 5 cm and R = 5 cm. Since the base radius equals the slant height, this is a special case.
r=R=5 cmr = R = 5 \text{ cm}
Step 2: Apply the cone angle formula.
θcone=360°×55=360°\theta_{\text{cone}} = \frac{360° \times 5}{5} = 360°
Step 3: A cone angle of 360° means no sector is removed at all. This corresponds to a completely flat disk — a degenerate cone with zero height. The semi-vertical angle of the cone is 90°.
θtakeout=360°360°=0°\theta_{\text{takeout}} = 360° - 360° = 0°
Step 4: Verify: for a valid pointed cone, you need r < R. Here r = R, so the cone collapses to a flat circle.
r<R    θcone<360°r < R \implies \theta_{\text{cone}} < 360°
Answer: The cone angle would be 360°, meaning no paper is removed and no actual cone forms. This edge case shows that you need r < R (base radius strictly less than slant height) to create a proper cone.

Frequently Asked Questions

What is the difference between cone angle and takeout angle?
The cone angle and the takeout angle are complementary parts of the full 360° disk. The takeout angle is the central angle of the sector you remove from the disk. The cone angle is the central angle of the sector that remains — the piece you roll into a cone. They always add up to 360°.
How do you find the cone angle from the base radius and slant height?
Use the formula θ_cone = 360° × r / R, where r is the base radius and R is the slant height (which equals the radius of the flat disk). This works because when you roll the sector into a cone, the arc length of the remaining sector must equal the circumference of the cone's circular base.
Why does the cone angle formula involve the ratio r/R?
When you roll the flat sector into a cone, the arc of the sector becomes the base circle. The arc length of a sector with angle θ and radius R is (θ/360°) × 2πR. Setting this equal to the base circumference 2πr and solving for θ gives θ = 360° × r/R. The ratio r/R directly controls how much of the disk is used.

Cone Angle vs. Takeout Angle

Cone AngleTakeout Angle
DefinitionCentral angle of the sector that remains and forms the coneCentral angle of the sector that is removed (cut out)
Formulaθ_cone = 360° × r / Rθ_takeout = 360° − 360° × r / R = 360°(1 − r/R)
RangeBetween 0° (exclusive) and 360° (exclusive) for a valid coneBetween 0° (exclusive) and 360° (exclusive) for a valid cone
Relationshipθ_cone = 360° − θ_takeoutθ_takeout = 360° − θ_cone
When to useWhen you need to know how large the remaining paper sector isWhen you need to know how much paper to cut away

Why It Matters

The cone angle appears in geometry courses when studying surface area and nets of 3D solids. It is essential in practical applications like constructing funnels, party hats, and architectural roof structures from flat sheet material. Understanding the relationship between the cone angle and the cone's dimensions also reinforces the connection between arc length and circumference, a key concept in circle geometry.

Common Mistakes

Mistake: Confusing the cone angle with the takeout angle — using the removed sector's angle instead of the remaining sector's angle.
Correction: Remember: the cone angle is the angle you keep (the piece that rolls into the cone), not the piece you throw away. Cone angle + takeout angle = 360°.
Mistake: Using the cone's height instead of its slant height as R in the formula.
Correction: The radius of the flat disk equals the slant height of the cone, not its vertical height. If you know the height h and base radius r, first compute the slant height: R = √(r² + h²).

Related Terms