Mathwords logoMathwords

Young's Inequality — Definition, Formula & Examples

Young's inequality states that for positive real numbers aa and bb, and conjugate exponents pp and qq, the product abab is bounded above by a weighted sum of powers: app+bqq\frac{a^p}{p} + \frac{b^q}{q}. It provides a fundamental upper bound on products that appears throughout analysis.

Let a,b0a, b \geq 0 and let p,q>1p, q > 1 satisfy 1p+1q=1\frac{1}{p} + \frac{1}{q} = 1. Then abapp+bqqab \leq \frac{a^p}{p} + \frac{b^q}{q}, with equality if and only if ap=bqa^p = b^q. This follows from the concavity of the logarithm (or equivalently, from the convexity of the exponential function).

Key Formula

abapp+bqqab \leq \frac{a^p}{p} + \frac{b^q}{q}
Where:
  • a,ba, b = Non-negative real numbers
  • pp = Exponent with $p > 1$
  • qq = Conjugate exponent satisfying $\frac{1}{p} + \frac{1}{q} = 1$

How It Works

Young's inequality converts a product into a sum, which is often easier to estimate. You identify the conjugate exponents pp and qq satisfying 1p+1q=1\frac{1}{p} + \frac{1}{q} = 1, then apply the bound directly. A common special case is p=q=2p = q = 2, which gives aba22+b22ab \leq \frac{a^2}{2} + \frac{b^2}{2}, the AM-GM inequality for two terms. In proofs involving LpL^p spaces, you typically set aa and bb to be strategically chosen functions or norms, then integrate both sides to derive Hölder's inequality.

Worked Example

Problem: Verify Young's inequality for a=3a = 3, b=9b = 9, p=3p = 3, q=32q = \frac{3}{2}.
Check conjugate exponents: Confirm that 1p+1q=1\frac{1}{p} + \frac{1}{q} = 1.
13+132=13+23=1\frac{1}{3} + \frac{1}{\frac{3}{2}} = \frac{1}{3} + \frac{2}{3} = 1 \checkmark
Compute the left side: Calculate the product abab.
ab=39=27ab = 3 \cdot 9 = 27
Compute the right side: Evaluate app+bqq\frac{a^p}{p} + \frac{b^q}{q}.
333+93/232=273+2732=9+18=27\frac{3^3}{3} + \frac{9^{3/2}}{\frac{3}{2}} = \frac{27}{3} + \frac{27}{\frac{3}{2}} = 9 + 18 = 27
Answer: Both sides equal 27, confirming abapp+bqqab \leq \frac{a^p}{p} + \frac{b^q}{q} with equality. Equality holds because ap=33=27=93/2=bqa^p = 3^3 = 27 = 9^{3/2} = b^q.

Why It Matters

Young's inequality is the key step in proving Hölder's inequality, which in turn underpins the Minkowski inequality and much of LpL^p space theory. If you study real analysis, functional analysis, or PDE theory, you will encounter it repeatedly as a tool for decoupling products into manageable sums.

Common Mistakes

Mistake: Forgetting that pp and qq must be conjugate exponents (1p+1q=1\frac{1}{p} + \frac{1}{q} = 1) and using arbitrary exponents instead.
Correction: Always verify the conjugate condition first. Given pp, compute q=pp1q = \frac{p}{p-1} before applying the inequality.