System of Nonlinear Equations — Definition, Formula & Examples
A system of nonlinear equations is a set of two or more equations, solved together, where at least one equation is not linear. Its graph can include curves such as circles or parabolas, and every point where all the graphs meet is a solution.
A system of equations in variables is nonlinear if at least one equation cannot be written in the form with constants and . A solution is an ordered -tuple that satisfies every equation in the system at the same time. Over the real numbers, the solution set is the intersection of the graphs of the equations.
How It Works
Substitution is usually the best method. Solve the simpler equation (often the linear one) for one variable, then substitute that expression into the other equation. This produces a single equation in one variable, often a quadratic. Solve it, then back-substitute each value to find the matching value of the other variable. Graphically, each real solution is an intersection point. For example, a line and a circle meet at 0, 1, or 2 points.
Worked Example
Problem: Solve the system and .
Step 1: The second equation already gives y in terms of x. Substitute for y in the circle equation, then expand.
Step 2: Subtract 25 from both sides, then divide every term by 2. Factor the quadratic and solve for x.
Step 3: Back-substitute each x-value into the linear equation to get its y-value.
Answer: The solutions are and . On a graph, these are the two points where the line crosses the circle of radius 5.
Why It Matters
In Algebra 2 and precalculus, you use these systems to find where a line crosses a parabola or circle. Physics and engineering problems use them too, such as finding when a thrown ball reaches a given height or where two orbits cross.
Common Mistakes
Mistake: Finding y by substituting x back into the nonlinear equation and keeping every result. With in , you get , so the false pair sneaks in.
Correction: Back-substitute into the linear equation, or check every pair in both original equations. The pair fails because , not .
