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Simultaneous Equations

Simultaneous Equations
System of Equations

Two or more equations containing common variable(s).

 

Example system of two simultaneous equations: x² + y² = 2 and x + y = 1


 

See also

Linear system of equations, solution

Key Formula

{a1x+b1y=c1a2x+b2y=c2\begin{cases} a_1 x + b_1 y = c_1 \\ a_2 x + b_2 y = c_2 \end{cases}
Where:
  • x,yx, y = The unknown variables common to both equations
  • a1,a2a_1, a_2 = Coefficients of x in the first and second equations
  • b1,b2b_1, b_2 = Coefficients of y in the first and second equations
  • c1,c2c_1, c_2 = Constants on the right-hand side of each equation

Worked Example

Problem: Solve the simultaneous equations: 2x + y = 11 and x − y = 1.
Step 1: Label the equations for reference.
(1)  2x+y=11(2)  xy=1\text{(1)}\; 2x + y = 11 \qquad \text{(2)}\; x - y = 1
Step 2: Add equation (1) and equation (2) to eliminate y. The +y and −y cancel out.
(2x+y)+(xy)=11+1    3x=12(2x + y) + (x - y) = 11 + 1 \implies 3x = 12
Step 3: Solve for x by dividing both sides by 3.
x=123=4x = \frac{12}{3} = 4
Step 4: Substitute x = 4 back into equation (1) to find y.
2(4)+y=11    8+y=11    y=32(4) + y = 11 \implies 8 + y = 11 \implies y = 3
Step 5: Check: substitute x = 4 and y = 3 into equation (2).
43=1  4 - 3 = 1 \; \checkmark
Answer: x = 4, y = 3

Another Example

This example uses the substitution method instead of the elimination method, showing an alternative approach when coefficients do not cancel easily by addition or subtraction.

Problem: Solve the simultaneous equations: 3x + 2y = 16 and x + 4y = 22.
Step 1: Label the equations. This time the coefficients don't cancel directly, so use the substitution method. Rearrange equation (2) to express x in terms of y.
(1)  3x+2y=16(2)  x+4y=22\text{(1)}\; 3x + 2y = 16 \qquad \text{(2)}\; x + 4y = 22
Step 2: From equation (2), isolate x.
x=224yx = 22 - 4y
Step 3: Substitute this expression for x into equation (1).
3(224y)+2y=16    6612y+2y=163(22 - 4y) + 2y = 16 \implies 66 - 12y + 2y = 16
Step 4: Simplify and solve for y.
10y=1666=50    y=5-10y = 16 - 66 = -50 \implies y = 5
Step 5: Substitute y = 5 back to find x.
x=224(5)=2220=2x = 22 - 4(5) = 22 - 20 = 2
Answer: x = 2, y = 5

Frequently Asked Questions

What is the difference between substitution and elimination for simultaneous equations?
In the substitution method, you rearrange one equation to express one variable in terms of the other, then substitute that expression into the second equation. In the elimination method, you add or subtract the equations (sometimes after multiplying one or both) so that one variable cancels out. Both methods give the same answer; the choice depends on which looks simpler for the given coefficients.
Can simultaneous equations have no solution or infinitely many solutions?
Yes. If the two equations represent parallel lines (same slope, different intercept), there is no point of intersection and no solution — the system is called inconsistent. If the two equations represent the same line (one is a multiple of the other), every point on that line is a solution, giving infinitely many solutions.
How many equations do you need to solve for n unknowns?
In general, you need at least n independent equations to find a unique solution for n unknowns. For example, two unknowns require two equations, and three unknowns require three equations. If you have fewer equations than unknowns, the system is underdetermined and typically has infinitely many solutions.

Elimination Method vs. Substitution Method

Elimination MethodSubstitution Method
Core ideaAdd or subtract equations to cancel one variableExpress one variable in terms of the other and substitute
Best whenCoefficients of one variable are equal or easy to make equalOne equation already has a variable with coefficient 1
Number of stepsOften fewer algebraic manipulations for linear systemsCan involve more rearranging but is very systematic
Risk of errorSign errors when subtracting equationsErrors when expanding brackets after substitution

Why It Matters

Simultaneous equations appear throughout GCSE and algebra courses and form the foundation for solving real-world problems where multiple conditions must hold at once — such as finding the price of two items given total costs, or determining where two lines intersect on a graph. They are also a prerequisite for studying matrices, linear programming, and systems of equations in higher mathematics and science.

Common Mistakes

Mistake: Forgetting to multiply every term in an equation when scaling before elimination.
Correction: When you multiply an equation by a constant, every term on both sides must be multiplied. For example, multiplying x + 2y = 5 by 3 gives 3x + 6y = 15, not 3x + 2y = 15.
Mistake: Substituting back into the wrong equation and missing an error.
Correction: After finding one variable, substitute into one equation to find the other — but always check your answer in the equation you did NOT use for substitution. This independent check catches arithmetic mistakes.

Related Terms