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Separable Differential Equation: Definition & How to Solve

Separable Differential Equation

A first order ordinary differential equation which can be solved by separating all occurrences of the two variables on either side of the equal sign and then integrating.

Example: dydx=x2y\frac{dy}{dx}=\frac{x^2}{y}Solution: dydx=x2yy dy=x2 dx∫y dy=∫x2 dx12y2=13x3+Cy2=23x3+Cy=±23x3+C\begin{aligned} \frac{dy}{dx}&=\frac{x^2}{y} \\ y\,dy&=x^2\,dx \\ \int y\,dy&=\int x^2\,dx \\ \frac{1}{2}y^2&=\frac{1}{3}x^3+C \\ y^2&=\frac{2}{3}x^3+C \\ y&=\pm\sqrt{\frac{2}{3}x^3+C} \end{aligned}

See also

Differential equation, ordinary differential equation

Key Formula

dydx=f(x) g(y)⟹1g(y) dy=f(x) dx⟹∫1g(y) dy=∫f(x) dx\frac{dy}{dx} = f(x)\,g(y) \quad\Longrightarrow\quad \frac{1}{g(y)}\,dy = f(x)\,dx \quad\Longrightarrow\quad \int \frac{1}{g(y)}\,dy = \int f(x)\,dx
Where:
  • yy = The dependent variable (unknown function of x)
  • xx = The independent variable
  • f(x)f(x) = A function of x only
  • g(y)g(y) = A function of y only
  • dydx\frac{dy}{dx} = The derivative of y with respect to x

Worked Example

Problem: Solve the differential equation dy/dx = 3x²y.
Step 1: Identify the separable form. The right side is the product of a function of x and a function of y.
dydx=3x2⋅y⇒f(x)=3x2,  g(y)=y\frac{dy}{dx} = 3x^2 \cdot y \quad\Rightarrow\quad f(x) = 3x^2,\; g(y) = y
Step 2: Separate the variables by dividing both sides by y and multiplying both sides by dx.
1y dy=3x2 dx\frac{1}{y}\,dy = 3x^2\,dx
Step 3: Integrate both sides independently.
∫1y dy=∫3x2 dx⇒ln⁡∣y∣=x3+C\int \frac{1}{y}\,dy = \int 3x^2\,dx \quad\Rightarrow\quad \ln|y| = x^3 + C
Step 4: Solve for y by exponentiating both sides.
∣y∣=ex3+C=eC⋅ex3⇒y=Aex3|y| = e^{x^3 + C} = e^C \cdot e^{x^3} \quad\Rightarrow\quad y = Ae^{x^3}
Step 5: Here A = ±e^C is an arbitrary constant. Note that y = 0 is also a solution (set A = 0).
y=Aex3,A∈Ry = Ae^{x^3}, \quad A \in \mathbb{R}
Answer: The general solution is y = Ae^(x³), where A is an arbitrary constant.

Another Example

This example includes an initial condition (initial value problem) and shows a case where the solution is given implicitly or requires a cube root, unlike the first example where the solution was a clean exponential.

Problem: Solve the initial value problem dy/dx = (x + 1)/(y²) with y(0) = 2.
Step 1: Separate variables by multiplying both sides by y² and by dx.
y2 dy=(x+1) dxy^2\,dy = (x + 1)\,dx
Step 2: Integrate both sides.
∫y2 dy=∫(x+1) dx⇒y33=x22+x+C\int y^2\,dy = \int (x+1)\,dx \quad\Rightarrow\quad \frac{y^3}{3} = \frac{x^2}{2} + x + C
Step 3: Apply the initial condition y(0) = 2 to find C.
(2)33=02+0+C⇒C=83\frac{(2)^3}{3} = \frac{0}{2} + 0 + C \quad\Rightarrow\quad C = \frac{8}{3}
Step 4: Write the particular solution and solve for y.
y33=x22+x+83⇒y3=3x22+3x+8⇒y=(3x22+3x+8)1/3\frac{y^3}{3} = \frac{x^2}{2} + x + \frac{8}{3} \quad\Rightarrow\quad y^3 = \frac{3x^2}{2} + 3x + 8 \quad\Rightarrow\quad y = \left(\frac{3x^2}{2} + 3x + 8\right)^{1/3}
Answer: y = ((3x²/2) + 3x + 8)^(1/3)

Frequently Asked Questions

How do you know if a differential equation is separable?
A first-order ODE is separable if you can write dy/dx as a product of a function of x alone and a function of y alone, i.e., dy/dx = f(x)·g(y). If the right side mixes x and y in a way that cannot be factored into such a product — for example, dy/dx = x + y — then the equation is not separable.
What is the difference between a separable and a linear differential equation?
A separable equation has the form dy/dx = f(x)·g(y), where variables can be split to opposite sides. A first-order linear equation has the form dy/dx + P(x)y = Q(x) and is solved using an integrating factor. Some equations are both separable and linear (like dy/dx = 2xy), while others are one but not the other.
Can you lose solutions when separating variables?
Yes. When you divide by g(y) to separate variables, any value of y where g(y) = 0 may be a constant solution (called an equilibrium or singular solution) that gets lost. You should always check whether g(y) = 0 produces a valid solution and state it separately if it does.

Separable Differential Equation vs. First-Order Linear Differential Equation

Separable Differential EquationFirst-Order Linear Differential Equation
Standard Formdy/dx = f(x)·g(y)dy/dx + P(x)y = Q(x)
Solution MethodSeparate variables, then integrate both sidesMultiply by integrating factor μ(x) = e^(∫P(x)dx)
Can be nonlinear in y?Yes (e.g., dy/dx = xy²)No — y and dy/dx appear only to the first power
OverlapSome separable equations are also linearSome linear equations are also separable
Exampledy/dx = x/ydy/dx + 2y = e^x

Why It Matters

Separable differential equations are typically the first type of ODE you learn to solve in a calculus or differential equations course, making them foundational. They model many real-world processes — exponential growth and decay, Newton's law of cooling, and simple population models are all separable. Mastering the separation-of-variables technique also builds the intuition needed for more advanced methods like integrating factors and substitution.

Common Mistakes

Mistake: Forgetting to check for lost solutions when dividing by g(y).
Correction: Before dividing by g(y), note any values where g(y) = 0. These may yield constant solutions (e.g., y = 0) that the general solution misses. Always check and list them separately.
Mistake: Forgetting the constant of integration or placing +C on both sides.
Correction: When you integrate both sides, each side technically gets its own constant, but you only need one. Combine them into a single constant C on one side of the equation. Omitting C entirely loses the family of solutions.

Related Terms