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Obelisk — Definition, Formula & Examples

An obelisk is a three-dimensional solid that has a rectangular base, a smaller rectangular top parallel to the base, and four trapezoidal faces connecting them. Unlike a frustum of a pyramid, the base and top rectangles do not need to be similar — they can have different length-to-width ratios.

An obelisk is a prismatoid whose two parallel faces (the base and top) are rectangles with dimensions a×ba \times b and c×dc \times d respectively, where the centers of the two rectangles are aligned along a perpendicular axis of height hh. Each lateral face is a trapezoid. When c=d=0c = d = 0, the obelisk reduces to a rectangular pyramid; when a=ca = c and b=db = d, it becomes a rectangular prism.

Key Formula

V=h6(ab+cd+(a+c)(b+d))V = \frac{h}{6}\bigl(ab + cd + (a+c)(b+d)\bigr)
Where:
  • VV = Volume of the obelisk
  • aa = Length of the base rectangle
  • bb = Width of the base rectangle
  • cc = Length of the top rectangle
  • dd = Width of the top rectangle
  • hh = Perpendicular height between the base and top

How It Works

To find the volume of an obelisk, you use a formula derived from the prismoidal formula, which generalizes volume calculations for solids bounded by two parallel planes. You need five measurements: the length aa and width bb of the base rectangle, the length cc and width dd of the top rectangle, and the perpendicular height hh between them. The formula accounts for the way the cross-section changes from one rectangle to the other. This shape appears in architecture, monument design, and excavation calculations where a trench tapers from a wider bottom to a narrower top.

Worked Example

Problem: Find the volume of an obelisk with a base of 6 m × 4 m, a top of 3 m × 2 m, and a height of 9 m.
Identify measurements: Base: a = 6, b = 4. Top: c = 3, d = 2. Height: h = 9.
Compute each product in the formula: Find ab, cd, and (a+c)(b+d).
ab=6×4=24,cd=3×2=6,(a+c)(b+d)=9×6=54ab = 6 \times 4 = 24, \quad cd = 3 \times 2 = 6, \quad (a+c)(b+d) = 9 \times 6 = 54
Sum the three terms: Add the three results together.
24+6+54=8424 + 6 + 54 = 84
Multiply by h/6: Apply the leading factor.
V=96×84=1.5×84=126 m3V = \frac{9}{6} \times 84 = 1.5 \times 84 = 126 \text{ m}^3
Answer: The volume of the obelisk is 126 m³.

Another Example

Problem: Verify that the obelisk formula gives the correct volume for a rectangular pyramid with base 10 m × 8 m and height 12 m (top dimensions c = 0 and d = 0).
Set up the formula: With c = 0 and d = 0, the formula simplifies.
V=h6(ab+0+(a+0)(b+0))=h6(ab+ab)=h6(2ab)=hab3V = \frac{h}{6}\bigl(ab + 0 + (a+0)(b+0)\bigr) = \frac{h}{6}(ab + ab) = \frac{h}{6}(2ab) = \frac{hab}{3}
Substitute values: Plug in a = 10, b = 8, h = 12.
V=12×10×83=9603=320 m3V = \frac{12 \times 10 \times 8}{3} = \frac{960}{3} = 320 \text{ m}^3
Check against pyramid formula: The standard pyramid volume is (1/3) × base area × height.
V=13(80)(12)=320 m3V = \frac{1}{3}(80)(12) = 320 \text{ m}^3 \checkmark
Answer: Both formulas give 320 m³, confirming the obelisk formula reduces correctly to the pyramid formula.

Why It Matters

The obelisk formula is used in civil engineering and construction to calculate earthwork volumes when trenches, embankments, or foundations taper from one rectangular cross-section to another. In high-school and college solid geometry courses, it demonstrates how the prismoidal formula unifies volume calculations for prisms, pyramids, and frustums under a single framework.

Common Mistakes

Mistake: Using the frustum formula when the base and top rectangles are not similar.
Correction: The frustum formula assumes similar cross-sections. When the top and base rectangles have different length-to-width ratios, you must use the obelisk (prismoidal) formula instead.
Mistake: Forgetting the mixed term (a+c)(b+d) and averaging only the two rectangular areas.
Correction: A simple average of the top and base areas ignores how the shape transitions between them. The middle term (a+c)(b+d) accounts for the cross-sectional area at the midpoint and is essential for accuracy.

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