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Natural Logarithm of 10 — Definition, Formula & Examples

The natural logarithm of 10, written ln10\ln 10, is the power you must raise ee to in order to get 10. Its approximate value is 2.302585.

ln10\ln 10 is the unique real number xx satisfying ex=10e^x = 10, where e2.71828e \approx 2.71828 is Euler's number. Its value to six decimal places is 2.3025852.302585.

Key Formula

ln10=loge102.302585\ln 10 = \log_e 10 \approx 2.302585
Where:
  • ln\ln = The natural logarithm function (base e)
  • ee = Euler's number, approximately 2.71828

How It Works

Because e2.30258510e^{2.302585} \approx 10, the value ln10\ln 10 acts as a conversion factor between natural logarithms and common (base-10) logarithms. The change of base formula states log10x=lnxln10\log_{10} x = \frac{\ln x}{\ln 10}, so dividing any natural logarithm by ln10\ln 10 converts it to a base-10 logarithm. This constant appears frequently when solving exponential equations that mix bases ee and 1010.

Worked Example

Problem: Convert ln50\ln 50 to a common logarithm (base 10) using ln10\ln 10.
Apply the change of base formula: Divide the natural logarithm by ln10\ln 10 to convert to base 10.
log1050=ln50ln10\log_{10} 50 = \frac{\ln 50}{\ln 10}
Substitute known values: A calculator gives ln503.91202\ln 50 \approx 3.91202. Use ln102.30259\ln 10 \approx 2.30259.
log10503.912022.302591.69897\log_{10} 50 \approx \frac{3.91202}{2.30259} \approx 1.69897
Answer: log10501.699\log_{10} 50 \approx 1.699, which matches the common logarithm of 50.

Why It Matters

Whenever you solve exponential growth or decay problems using ee but need a base-10 answer (for example, pH in chemistry or decibels in physics), ln10\ln 10 is the bridge between the two logarithm bases. Memorizing that ln102.303\ln 10 \approx 2.303 saves time on exams where calculator access is limited.

Common Mistakes

Mistake: Confusing ln10\ln 10 with log10e\log_{10} e.
Correction: These are reciprocals: log10e0.4343\log_{10} e \approx 0.4343 while ln102.3026\ln 10 \approx 2.3026. Notice ln10×log10e=1\ln 10 \times \log_{10} e = 1.