Problem: Show that the vectors (1, 0, 0, 0), (0, 1, 0, 0), (0, 0, 1, 0), and (0, 0, 0, 1) confirm that ℝ⁴ is 4-dimensional, and express the point (3, −2, 5, 7) using these vectors.
Step 1: Check independence: none of the four vectors can be written as a linear combination of the others. Each vector has a 1 in a unique position and 0s elsewhere, so no combination of the other three can produce that 1.
e1=(1,0,0,0),e2=(0,1,0,0),e3=(0,0,1,0),e4=(0,0,0,1) Step 2: Since we found 4 independent vectors, the space has at least 4 dimensions.
Step 3: Any 5th vector in ℝ⁴ can be written as a linear combination of these four. For example, (3, −2, 5, 7) decomposes as:
3e1+(−2)e2+5e3+7e4=(3,−2,5,7) Step 4: Because we can find exactly 4 independent vectors but never 5, the space ℝ⁴ is 4-dimensional. You need exactly 4 coordinates to locate any point.
Answer: The four standard basis vectors are independent and span all of ℝ⁴, confirming it is 4-dimensional. The point (3, −2, 5, 7) requires all 4 coordinates and is a linear combination of the four basis vectors.