Direct Sum — Definition, Formula & Examples
Direct sum is a way of combining two or more vector spaces (or subspaces) into a larger one where each element can be written uniquely as a sum of elements from the component spaces.
Given vector spaces and over a field , the direct sum is the vector space of all ordered pairs with and , equipped with componentwise addition and scalar multiplication. For subspaces of a vector space , we write when and .
Key Formula
Where:
- = The ambient vector space
- = Subspaces of V
- = Direct sum symbol
How It Works
When you form the direct sum , the dimension of the result equals . Every vector in the direct sum decomposes uniquely into one component from each summand — this uniqueness is what distinguishes a direct sum from an ordinary sum of subspaces. You can recognize an internal direct sum by checking two conditions: the subspaces together span the whole space, and their intersection is only the zero vector.
Worked Example
Problem: Let W₁ = {(a, 0) : a ∈ ℝ} and W₂ = {(0, b) : b ∈ ℝ} be subspaces of ℝ². Show that ℝ² = W₁ ⊕ W₂.
Step 1: Check that W₁ + W₂ = ℝ². Any vector (x, y) in ℝ² can be written as (x, 0) + (0, y), where (x, 0) ∈ W₁ and (0, y) ∈ W₂.
Step 2: Check that W₁ ∩ W₂ = {(0, 0)}. A vector in both W₁ and W₂ must have the form (a, 0) and (0, b) simultaneously, forcing a = 0 and b = 0.
Step 3: Both conditions are satisfied, so ℝ² is the direct sum of W₁ and W₂. Note that dim(W₁) + dim(W₂) = 1 + 1 = 2 = dim(ℝ²).
Answer: ℝ² = W₁ ⊕ W₂, confirming that every vector in ℝ² decomposes uniquely into a horizontal and vertical component.
Why It Matters
Direct sums appear throughout linear algebra whenever you decompose a space into independent pieces — for instance, splitting ℝⁿ into eigenspaces of a diagonalizable matrix. In abstract algebra, the same idea generalizes to modules and groups, making it foundational for courses in representation theory and algebraic topology.
Common Mistakes
Mistake: Confusing a direct sum with an ordinary sum of subspaces. Students write V = W₁ ⊕ W₂ whenever W₁ + W₂ = V, ignoring the intersection condition.
Correction: A direct sum requires both that the subspaces span V and that their intersection is {0}. Without the trivial intersection, decompositions are not unique, and the sum is not direct.
