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Chebyshev Polynomial of the First Kind — Definition, Formula & Examples

Chebyshev polynomials of the first kind are a sequence of orthogonal polynomials Tn(x)T_n(x) defined on [1,1][-1,1] that satisfy Tn(cosθ)=cos(nθ)T_n(\cos\theta) = \cos(n\theta). They arise naturally in approximation theory, where they minimize the maximum error when approximating functions by polynomials.

For each non-negative integer nn, the Chebyshev polynomial of the first kind Tn(x)T_n(x) is the unique polynomial of degree nn satisfying Tn(cosθ)=cos(nθ)T_n(\cos\theta) = \cos(n\theta) for all θR\theta \in \mathbb{R}. Equivalently, TnT_n can be defined by the recurrence T0(x)=1T_0(x)=1, T1(x)=xT_1(x)=x, and Tn+1(x)=2xTn(x)Tn1(x)T_{n+1}(x)=2xT_n(x)-T_{n-1}(x). These polynomials are orthogonal on [1,1][-1,1] with respect to the weight function w(x)=(1x2)1/2w(x)=(1-x^2)^{-1/2}.

Key Formula

Tn+1(x)=2xTn(x)Tn1(x)T_{n+1}(x) = 2x\,T_n(x) - T_{n-1}(x)
Where:
  • Tn(x)T_n(x) = Chebyshev polynomial of the first kind of degree $n$
  • xx = Variable, typically restricted to $[-1,1]$
  • nn = Non-negative integer degree

How It Works

You can generate any Chebyshev polynomial using the three-term recurrence relation: start with T0(x)=1T_0(x)=1 and T1(x)=xT_1(x)=x, then repeatedly apply Tn+1(x)=2xTn(x)Tn1(x)T_{n+1}(x)=2xT_n(x)-T_{n-1}(x). For small arguments, the trigonometric definition Tn(cosθ)=cos(nθ)T_n(\cos\theta)=\cos(n\theta) lets you evaluate the polynomial directly. The roots of Tn(x)T_n(x) are xk=cos ⁣(2k12nπ)x_k = \cos\!\left(\frac{2k-1}{2n}\pi\right) for k=1,,nk=1,\dots,n, and these roots serve as optimal interpolation nodes that minimize Runge's phenomenon.

Worked Example

Problem: Use the recurrence relation to find T3(x)T_3(x).
Base cases: Start with the first two Chebyshev polynomials.
T0(x)=1,T1(x)=xT_0(x) = 1, \quad T_1(x) = x
Compute T₂: Apply the recurrence with n=1n=1.
T2(x)=2xT1(x)T0(x)=2x21T_2(x) = 2x \cdot T_1(x) - T_0(x) = 2x^2 - 1
Compute T₃: Apply the recurrence again with n=2n=2.
T3(x)=2xT2(x)T1(x)=2x(2x21)x=4x33xT_3(x) = 2x \cdot T_2(x) - T_1(x) = 2x(2x^2 - 1) - x = 4x^3 - 3x
Answer: T3(x)=4x33xT_3(x) = 4x^3 - 3x. You can verify: T3(cosθ)=4cos3θ3cosθ=cos(3θ)T_3(\cos\theta) = 4\cos^3\theta - 3\cos\theta = \cos(3\theta), which matches the triple-angle formula.

Why It Matters

Chebyshev polynomials are the backbone of spectral methods in numerical analysis and scientific computing. Their roots provide the optimal nodes for polynomial interpolation, directly reducing approximation error in finite element analysis, signal processing filters, and computational physics simulations.

Common Mistakes

Mistake: Forgetting the factor of 2 in the recurrence and writing Tn+1(x)=xTn(x)Tn1(x)T_{n+1}(x) = xT_n(x) - T_{n-1}(x).
Correction: The correct recurrence is Tn+1(x)=2xTn(x)Tn1(x)T_{n+1}(x) = 2xT_n(x) - T_{n-1}(x). Missing the 2 produces incorrect polynomials for n2n \geq 2.