Mathwords logoMathwords

Cauchy Distribution — Definition, Formula & Examples

The Cauchy distribution is a continuous probability distribution shaped like a bell curve but with much heavier tails, meaning extreme values occur far more often than with a normal distribution. Its most distinctive property is that it has no defined mean or variance.

A continuous random variable XX follows a Cauchy distribution with location parameter x0x_0 and scale parameter γ>0\gamma > 0 if its probability density function is f(x)=1πγ[1+(xx0γ)2]f(x) = \frac{1}{\pi\gamma\left[1 + \left(\frac{x - x_0}{\gamma}\right)^2\right]} for x(,)x \in (-\infty, \infty). The standard Cauchy distribution sets x0=0x_0 = 0 and γ=1\gamma = 1, and is equivalent to a tt-distribution with 1 degree of freedom.

Key Formula

f(x)=1πγ[1+(xx0γ)2]f(x) = \frac{1}{\pi\gamma\left[1 + \left(\frac{x - x_0}{\gamma}\right)^2\right]}
Where:
  • x0x_0 = Location parameter (the peak/median of the distribution)
  • γ\gamma = Scale parameter (half-width at half-maximum), must be positive
  • xx = The continuous random variable

How It Works

The location parameter x0x_0 shifts the peak of the distribution left or right, similar to the mean in a normal distribution. The scale parameter γ\gamma controls the width, analogous to standard deviation. Because the tails decay so slowly (proportional to 1/x21/x^2 rather than exponentially), the integral that would define the mean diverges. This means the sample mean of Cauchy data does not converge to a fixed value as you collect more data — the law of large numbers does not apply. The Cauchy distribution arises naturally as the ratio of two independent standard normal random variables.

Worked Example

Problem: Find the probability density of the standard Cauchy distribution at x = 1.
Set parameters: The standard Cauchy has location x₀ = 0 and scale γ = 1.
x0=0,γ=1x_0 = 0, \quad \gamma = 1
Substitute into the PDF: Plug x = 1 into the formula.
f(1)=1π1[1+(101)2]=1π(1+1)f(1) = \frac{1}{\pi \cdot 1 \cdot \left[1 + \left(\frac{1 - 0}{1}\right)^2\right]} = \frac{1}{\pi(1 + 1)}
Simplify: Compute the final value.
f(1)=12π0.1592f(1) = \frac{1}{2\pi} \approx 0.1592
Answer: The standard Cauchy PDF evaluated at x = 1 is approximately 0.1592. For comparison, the standard normal PDF at x = 1 is about 0.2420 — the Cauchy is lower near the center but much higher in the tails.

Visualization

Why It Matters

The Cauchy distribution is a key counterexample in statistics courses: it shows that not every distribution has a mean or variance, and that the central limit theorem requires finite variance. In physics, the same distribution appears as the Lorentzian or Breit-Wigner distribution, describing resonance phenomena in spectroscopy and particle physics.

Common Mistakes

Mistake: Assuming the Cauchy distribution has a mean of 0 because it is symmetric around its peak.
Correction: Symmetry alone does not guarantee that the mean exists. The integral defining the expected value diverges for the Cauchy distribution, so the mean is undefined — not zero.