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Absolute Value Inequality — Definition, Rules & Examples

An absolute value inequality is an inequality that contains an absolute value expression, such as ∣x−3∣<5|x - 3| < 5 or ∣2x+1∣≥7|2x + 1| \geq 7. Solving one produces a compound inequality — either an "and" inequality (for less-than) or an "or" inequality (for greater-than).

An absolute value inequality is an inequality in which the variable appears inside an absolute value. For expressions of the form ∣A∣<b|A| < b (where b>0b > 0), the solution is the conjunction −b<A<b-b < A < b. For expressions of the form ∣A∣>b|A| > b, the solution is the disjunction A<−bA < -b or A>bA > b. These rules also apply when << and >> are replaced by ≤\leq and ≥\geq, respectively.

Key Formula

∣A∣<b  ⟹  −b<A<b∣A∣>b  ⟹  A<−b   or   A>b\begin{gathered}|A| < b \implies -b < A < b\\|A| > b \implies A < -b \;\text{ or }\; A > b\end{gathered}
Where:
  • AA = an algebraic expression (often containing a variable)
  • bb = a positive number representing the boundary value

Worked Example

Problem: Solve ∣2x−4∣≤10|2x - 4| \leq 10 and express the solution as an inequality and in interval notation.
Step 1: Since the inequality uses ≤ (less than or equal), rewrite it as a compound "and" inequality.
−10≤2x−4≤10-10 \leq 2x - 4 \leq 10
Step 2: Add 4 to all three parts to begin isolating x.
−10+4≤2x≤10+4−6≤2x≤14-10 + 4 \leq 2x \leq 10 + 4\\[6pt]-6 \leq 2x \leq 14
Step 3: Divide all three parts by 2.
−3≤x≤7-3 \leq x \leq 7
Step 4: Write the solution in interval notation.
[−3,  7][-3,\; 7]
Answer: The solution is −3≤x≤7-3 \leq x \leq 7, or in interval notation, [−3,7][-3, 7].

Visualization

Why It Matters

Absolute value inequalities show up whenever you need to describe a range of acceptable values around a target. In manufacturing, for instance, a machine part might need to be within 0.02 cm of a specified length — that tolerance is naturally expressed as an absolute value inequality. They also appear throughout statistics when measuring how far data points fall from a mean.

Common Mistakes

Mistake: Using an "and" compound inequality when the absolute value is greater than a number (or vice versa).
Correction: Remember: "less thAND" — if ∣A∣<b|A| < b, use an "and" inequality. "greatOR" — if ∣A∣>b|A| > b, use an "or" inequality. Mixing these up gives incorrect solution sets.
Mistake: Forgetting to isolate the absolute value expression before splitting into cases.
Correction: If the inequality is something like 3∣x+1∣−2>73|x + 1| - 2 > 7, first add 2 and divide by 3 to get ∣x+1∣>3|x + 1| > 3 before applying the rules.

Related Terms