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Segment of a Circle

Segment of a Circle

A part of the interior of a circle bounded by a chord and an arc.

 

Shaded circular segment with radius r and central angle θ. Area = ½r²(θ - sinθ) radians or ½r²(π/180·θ - sinθ) degrees.

 

 

See also

Radians, degrees, sine, area of a segment of a circle

Key Formula

A=r22(θsinθ)A = \frac{r^2}{2}\left(\theta - \sin\theta\right)
Where:
  • AA = Area of the segment
  • rr = Radius of the circle
  • θ\theta = Central angle subtended by the arc, measured in radians

Worked Example

Problem: A circle has radius 10 cm. A chord subtends a central angle of 90° (π/2 radians). Find the area of the minor segment.
Step 1: Convert the central angle to radians if needed. Here 90° = π/2 radians.
θ=π21.5708\theta = \frac{\pi}{2} \approx 1.5708
Step 2: Write down the segment area formula and substitute the known values.
A=r22(θsinθ)=1022(π2sinπ2)A = \frac{r^2}{2}\left(\theta - \sin\theta\right) = \frac{10^2}{2}\left(\frac{\pi}{2} - \sin\frac{\pi}{2}\right)
Step 3: Evaluate sin(π/2) = 1.
A=1002(π21)=50(π21)A = \frac{100}{2}\left(\frac{\pi}{2} - 1\right) = 50\left(\frac{\pi}{2} - 1\right)
Step 4: Compute the numerical value.
A=50(1.57081)=50×0.570828.54 cm2A = 50(1.5708 - 1) = 50 \times 0.5708 \approx 28.54 \text{ cm}^2
Answer: The area of the minor segment is approximately 28.54 cm².

Another Example

This example uses a different central angle (120° instead of 90°) and a different radius, reinforcing the same formula while showing that sin θ is not always a convenient value like 1.

Problem: A circle has radius 6 cm. A chord subtends a central angle of 120° at the centre. Find the area of the minor segment.
Step 1: Convert 120° to radians.
θ=120°×π180°=2π32.0944\theta = 120° \times \frac{\pi}{180°} = \frac{2\pi}{3} \approx 2.0944
Step 2: Substitute r = 6 and θ = 2π/3 into the formula.
A=622(2π3sin2π3)=18(2π3sin120°)A = \frac{6^2}{2}\left(\frac{2\pi}{3} - \sin\frac{2\pi}{3}\right) = 18\left(\frac{2\pi}{3} - \sin 120°\right)
Step 3: Evaluate sin 120° = √3/2 ≈ 0.8660.
A=18(2.09440.8660)=18×1.2284A = 18\left(2.0944 - 0.8660\right) = 18 \times 1.2284
Step 4: Compute the final value.
A22.11 cm2A \approx 22.11 \text{ cm}^2
Answer: The area of the minor segment is approximately 22.11 cm².

Frequently Asked Questions

What is the difference between a segment and a sector of a circle?
A sector is the 'pie-slice' region bounded by two radii and an arc. A segment is the region between a chord and its arc — essentially a sector with the triangle removed. You can find the segment area by subtracting the triangle area from the sector area, which is exactly what the formula A = (r²/2)(θ − sin θ) does.
How do you find the area of a major segment?
First find the area of the minor segment using the formula with the minor central angle θ. Then subtract it from the total area of the circle: Major segment area = πr² − minor segment area. Alternatively, use the formula directly with the reflex central angle (2π − θ) in place of θ.
Does the segment formula work when the angle is in degrees?
The formula A = (r²/2)(θ − sin θ) requires θ in radians. If your angle is in degrees, either convert to radians first (multiply by π/180) or use the degree-based version: A = (r²/2)(πα/180 − sin α), where α is the angle in degrees.

Segment of a Circle vs. Sector of a Circle

Segment of a CircleSector of a Circle
DefinitionRegion between a chord and its arcRegion between two radii and the arc they enclose
BoundaryOne chord + one arcTwo radii + one arc
Area formula (radians)A = (r²/2)(θ − sin θ)A = (r²/2)θ
RelationshipSegment = Sector − TriangleSector = Segment + Triangle
Shape analogyLike a "cap" cut by a straight lineLike a "pie slice"

Why It Matters

Segments of circles appear in many geometry and trigonometry problems, especially when calculating areas of overlapping circles or cross-sections of cylinders. You will encounter them in standardized tests (SAT, ACT, GCSE, and IB) as well as in real-world contexts like finding the cross-sectional area of water in a partially filled pipe. Mastering the segment area formula also strengthens your understanding of how radians, the sine function, and area formulas work together.

Common Mistakes

Mistake: Using degrees directly in the formula A = (r²/2)(θ − sin θ)
Correction: The θ in (θ − sin θ) must be in radians. If you plug in degrees, the subtraction θ − sin θ is dimensionally inconsistent and gives a wildly incorrect answer. Always convert degrees to radians first.
Mistake: Confusing a segment with a sector
Correction: A sector includes the triangular region formed by the two radii; a segment does not. If a problem asks for the segment, you need to subtract the triangle area from the sector area. The formula A = (r²/2)(θ − sin θ) already accounts for this subtraction.

Related Terms

  • CircleThe shape that contains the segment
  • ChordStraight-line boundary of the segment
  • Arc of a CircleCurved boundary of the segment
  • Area of a Segment of a CircleFormula and derivation for segment area
  • RadianAngle unit required in the segment formula
  • SineTrig function used in the area formula
  • InteriorA segment is part of a circle's interior
  • DegreeAlternative angle unit (must convert to radians)