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Infinite Geometric Series

Infinite Geometric Series

An infinite series that is geometric. An infinite geometric series converges if its common ratio r satisfies –1 < r < 1. Otherwise it diverges.

Infinite geometric series formulas: General Form a₁+a₁r+a₁r²+…, Sum=a₁/(1−r) if −1<r<1, with two examples showing convergent sums.

 

See also

Series, infinite, finite, geometric sequence

Key Formula

S=n=0arn=a1r,r<1S = \sum_{n=0}^{\infty} a r^n = \frac{a}{1 - r}, \quad |r| < 1
Where:
  • SS = The sum of the infinite geometric series
  • aa = The first term of the series
  • rr = The common ratio between consecutive terms
  • nn = The index of summation, starting from 0

Worked Example

Problem: Find the sum of the infinite geometric series: 12 + 6 + 3 + 1.5 + …
Step 1: Identify the first term a.
a=12a = 12
Step 2: Find the common ratio r by dividing the second term by the first term.
r=612=12r = \frac{6}{12} = \frac{1}{2}
Step 3: Check that the series converges by verifying |r| < 1.
12=12<1\left|\frac{1}{2}\right| = \frac{1}{2} < 1 \quad \checkmark
Step 4: Apply the sum formula.
S=a1r=12112=1212=24S = \frac{a}{1 - r} = \frac{12}{1 - \frac{1}{2}} = \frac{12}{\frac{1}{2}} = 24
Answer: The sum of the infinite geometric series is 24.

Another Example

This example involves a negative common ratio, which produces an alternating series. It shows how to handle the subtraction of a negative number in the denominator of the formula.

Problem: Find the sum of the infinite geometric series: 27 − 9 + 3 − 1 + …
Step 1: Identify the first term a.
a=27a = 27
Step 2: Find the common ratio r. Since the signs alternate, expect a negative ratio.
r=927=13r = \frac{-9}{27} = -\frac{1}{3}
Step 3: Check for convergence. The absolute value of r must be less than 1.
r=13=13<1|r| = \left|-\frac{1}{3}\right| = \frac{1}{3} < 1 \quad \checkmark
Step 4: Substitute into the sum formula. Be careful with the double negative in the denominator.
S=271(13)=271+13=2743=27×34=814=20.25S = \frac{27}{1 - \left(-\frac{1}{3}\right)} = \frac{27}{1 + \frac{1}{3}} = \frac{27}{\frac{4}{3}} = 27 \times \frac{3}{4} = \frac{81}{4} = 20.25
Answer: The sum of the infinite geometric series is 81/4, or 20.25.

Frequently Asked Questions

When does an infinite geometric series converge?
An infinite geometric series converges only when the absolute value of the common ratio satisfies |r| < 1, meaning r is between −1 and 1 (exclusive). When this condition holds, the terms get progressively smaller and approach zero, allowing the partial sums to settle toward a finite limit. If |r| ≥ 1, the terms do not shrink, so the series diverges.
What is the difference between a geometric sequence and an infinite geometric series?
A geometric sequence is an ordered list of numbers where each term is found by multiplying the previous term by a constant ratio. An infinite geometric series is what you get when you add up all the terms of that sequence. The sequence 3, 1.5, 0.75, … is a list; the series 3 + 1.5 + 0.75 + … represents a sum.
How do you convert a repeating decimal to a fraction using an infinite geometric series?
A repeating decimal can be written as an infinite geometric series. For example, 0.333… = 3/10 + 3/100 + 3/1000 + …, which is a geometric series with a = 3/10 and r = 1/10. Applying the formula gives S = (3/10)/(1 − 1/10) = (3/10)/(9/10) = 3/9 = 1/3. This technique works for any repeating decimal.

Infinite Geometric Series vs. Finite Geometric Series

Infinite Geometric SeriesFinite Geometric Series
Number of termsInfinitely many termsA specific number n of terms
FormulaS = a / (1 − r), requires |r| < 1S_n = a(1 − rⁿ) / (1 − r), works for any r ≠ 1
Convergence conditionOnly converges when |r| < 1Always produces a finite sum (it has finitely many terms)
When to useWhen summing all terms of a never-ending geometric patternWhen summing a known, fixed number of terms

Why It Matters

Infinite geometric series appear throughout precalculus and calculus as a foundational example of convergence. They provide a practical tool for converting repeating decimals to fractions and for solving real-world problems involving perpetual processes, such as calculating the total distance of a bouncing ball or the present value of a perpetuity in finance. Mastering this concept also prepares you for the study of power series and Taylor series in higher mathematics.

Common Mistakes

Mistake: Using the sum formula when |r| ≥ 1.
Correction: The formula S = a/(1 − r) is only valid when |r| < 1. If |r| ≥ 1, the series diverges and has no finite sum. Always check the convergence condition before applying the formula.
Mistake: Mishandling a negative common ratio in the denominator.
Correction: When r is negative, the denominator becomes 1 − (−|r|) = 1 + |r|. Students often write 1 − |r| instead, which gives the wrong answer. Substitute the actual signed value of r into the formula and simplify carefully.

Related Terms