Cardioid
A curve that is somewhat heart shaped. A cardioid can
be drawn by tracing the path of a point on
a circle as the circle
rolls around a fixed circle of the
same radius.
The equation is usually written in polar
coordinates.
Note: A cardioid is a special case of the limaçon
family of curves.
Cardioid: r = a ± a cos θ (horizontal)
or r = a ± a sin θ (vertical)

r = 2 + 2 cos θ |

r = 2 + 2 sin θ |
See
also
Polar
curves, cycloid
Worked Example
Problem: Find the key features of the cardioid r = 3 + 3 cos θ, and determine the coordinates of the point farthest from the origin.
Step 1: Identify the form. The equation matches r = a + a cos θ with a = 3, so this is a horizontal cardioid opening to the right.
r=3+3cosθ,a=3 Step 2: Find the maximum r. Since cos θ has a maximum value of 1, the farthest point occurs at θ = 0.
rmax=3+3(1)=6 Step 3: Find where r = 0 (the cusp). Set 3 + 3 cos θ = 0, which gives cos θ = −1, so the cusp is at θ = π.
3+3cosθ=0⟹cosθ=−1⟹θ=π Step 4: Convert the farthest point to Cartesian coordinates. At θ = 0 and r = 6: x = 6 cos 0 = 6 and y = 6 sin 0 = 0.
x=6cos0=6,y=6sin0=0⇒(6,0) Answer: The cardioid r = 3 + 3 cos θ has a maximum radius of 6, reached at the Cartesian point (6, 0), and a cusp at the origin when θ = π.
Another Example
This example applies integration to a cardioid, showing how to compute the enclosed area using the polar area formula — a common calculus exercise, unlike the first example which focused on identifying key features.
Problem: Find the area enclosed by the cardioid r = 2 + 2 sin θ.
Step 1: Recall the polar area formula. For a closed curve traced once as θ goes from 0 to 2π:
A=21∫02πr2dθ Step 2: Substitute r = 2 + 2 sin θ and expand the square.
r2=(2+2sinθ)2=4+8sinθ+4sin2θ Step 3: Use the identity sin²θ = (1 − cos 2θ)/2 to simplify.
r2=4+8sinθ+4⋅21−cos2θ=6+8sinθ−2cos2θ Step 4: Integrate over [0, 2π]. The integrals of sin θ and cos 2θ over a full period are both 0, leaving only the constant term.
A=21∫02π(6+8sinθ−2cos2θ)dθ=21⋅6⋅2π=6π Answer: The area enclosed by the cardioid r = 2 + 2 sin θ is 6π ≈ 18.85 square units.
Frequently Asked Questions
What is the difference between a cardioid and a limaçon?
A cardioid is a special case of the limaçon. The general limaçon has the form r = b + a cos θ. When b = a, the limaçon becomes a cardioid with a cusp at the origin. When b ≠ a, the curve is a limaçon that may have an inner loop (b < a), a dimple (a < b < 2a), or be convex (b ≥ 2a).
Why is a cardioid called 'heart-shaped'?
The name comes from the Greek word 'kardia,' meaning heart. When plotted, the curve has a rounded lobe on one side and a pointed cusp on the other, giving it a shape that loosely resembles a heart (or more precisely, the stylized heart symbol). The orientation depends on whether you use cos θ (horizontal) or sin θ (vertical).
How do you find the area of a cardioid?
Use the polar area formula A = (1/2)∫₀²π r² dθ. For any cardioid r = a + a cos θ (or the sin θ version), the enclosed area always equals 6πa²/4 = (3/2)πa², which simplifies nicely. For example, with a = 2, the area is 6π.
Cardioid vs. Limaçon
| Cardioid | Limaçon |
|---|
| General form | r = a + a cos θ (coefficients equal) | r = b + a cos θ (coefficients can differ) |
| Cusp or loop? | Always has a cusp at the origin | May have an inner loop, dimple, or be convex |
| Condition | b = a | b and a are any positive values |
| Enclosed area | (3/2)πa² | Depends on both a and b |
| Relationship | Special case of limaçon | General family that includes the cardioid |
Why It Matters
Cardioids appear in precalculus and calculus courses as a key example of polar curves, often used to practice polar graphing, finding areas, and computing arc lengths. They also show up in physics and engineering — for instance, many microphones have a "cardioid" pickup pattern, meaning they are most sensitive to sound from one direction, matching the shape of the curve. Understanding cardioids helps build intuition about how polar equations relate to the shapes they produce.
Common Mistakes
Mistake: Confusing cos θ and sin θ orientations: students assume r = a + a cos θ opens upward.
Correction: The cos θ form produces a cardioid symmetric about the horizontal (polar) axis, opening right (for +) or left (for −). The sin θ form is symmetric about the vertical axis, opening up (for +) or down (for −).
Mistake: Forgetting that both coefficients must be equal for a cardioid, writing something like r = 2 + 3 cos θ and calling it a cardioid.
Correction: If the constant term and the coefficient of cos θ (or sin θ) are not equal, the curve is a limaçon but not a cardioid. A cardioid requires the form r = a ± a cos θ or r = a ± a sin θ, where the two coefficients match.